Measurement of Elements: DGCA Air Navigation questions

For flight fuel of 2000 Kg calculated $D_{PNR}$ = 500 nm. If Flight Fuel is increased by 200 Kg, $D_{PNR}$ will be:

Full TAS 500 kt. Engine failure TAS 400 kt. Total distance 1000 nm. Along track wind component 40 kt. The distance to the engine failure CP will be:

The distance to the PNR will be greatest:

An engine failure PNR is calculated to enable the pilot to make the correct decision in the event of:

In flight it is discovered that the winds used have been reversed, the effect will be: